1/8^x=3=(2)(16)^2x-1

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Solution for 1/8^x=3=(2)(16)^2x-1 equation:



1/8^x=3=(2)(16)^2x-1
We move all terms to the left:
1/8^x-(3)=0
Domain of the equation: 8^x!=0
x!=0/1
x!=0
x∈R
We multiply all the terms by the denominator
-3*8^x+1=0
Wy multiply elements
-24x+1=0
We move all terms containing x to the left, all other terms to the right
-24x=-1
x=-1/-24
x=1/24

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